straighten

Timber Bolted Connection

CSA O86-01
v1.0.0
File:
Project:
Designer:
Date:

Members

Number of members:

Side Member(s)

Material:
Thickness:
mm
Orientation of load
Angle relative to grain:
deg
Loaded end distance (PR):
mm
Loaded edge distance (QR):
mm

Main Member

Material:
Thickness:
mm
Orientation of load
Angle relative to grain:
deg
Loaded end distance (PR):
mm
Loaded edge distance (QR):
mm

Bolts

Bolt diameter:
Yield strength, fy:
MPa
Ultimate strength, Fu:
MPa
Bolt rows are parallel to the applied load
Number of Rows:
Bolts Per Row:
Row Spacing:
mm
Bolt Spacing in row:
mm

Conditions

Wood:
Service:
Treatment:
Load Duration:
waiting for input...

Parallel to Grain - Lateral Resistance

(Both members loaded parallel to grain)
&Phi = 0.7
KT = 1.0
JG = 1
Joint detail = A
KD = 1
JR = 1
Bolt d = 9.525 mm
KSF = 1
JL = 1
JF = JG*JL*JR = 1
pu calculations
Gside = 0.49
f2 main = 27.93
(c) = n/a
(f) = 7577 N
ns = 1
f1 side = 27.93
(b) = 29795 N
(e) = 7909 N
pu = 3567 N
Gmain = 0.49
(a) = 8087 N
(d) = 3567 N
(g) = 3899 N
nf = 1
Pu=pu*KD*KSF*KT = 3.57 kN

Pr = &Phi*Pu*ns*nF*JF =2.5 kN

Perpendicular to Grain - Lateral Resistance

(Side member parallel to grain and main member perpendicular to grain)
&Phi = 0.7
KT = 1.0
Joint detail = A
KD = 1
Bolt d = 9.525 mm
KSF = 1
qu modes
Gside = 0.49
f2 main = 12.15
(c) = n/a
(f) = 4209 N
ns = 1
f1 side = 27.93
(b) = 12959 N
(e) = 7477 N
qu = 3036 N
JR = 1
Gmain = 0.49
(a) = 8087 N
(d) = 3135 N
(g) = 3036 N
nf = 1
Qu=qu*KD*KSF*KT = 3.04 kN

Qr = &Phi*Qu*ns*nF*JR =2.13 kN

Loads at Angle - Lateral Resistance

Main member parallel to grain, Side member perpendicular to grain
Qr = 1.55 kN
Nr side = 2.5 kN
Main member perpendicular to grain, Side member parallel to grain
Qr = 2.13 kN
Nr_ main = 2.13 kN

Nr = Pr*Qr/(Pr*sin2&Theta + Qr*cos2&Theta) =2.13 kN

This information must be read or used in conjunction with the 2005 reprint of CAN/CSA O86-01 Engineering Design in Wood.
In the event of discrepancies, CAN/CSA O-86 shall govern.