Timber Section
CSA O86-01
v1.0.0
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KSb = 1.0
Fb=fb(KD*KH*KSb*KT) = 16.5 MPa
KSv = 1.0
Fv=fv(KD*KH*KSv*KT) = 1.9 MPa
KSc = 1.0
Fc = fc(KD*KH*KSc*KT) = 19 MPa
A = b*d = 5320 mm2
KSt = 1.0
Ft = ft(KD*KH*KSt*KT) = 10.6 MPa
Properties
Section: 38 mm x 140 mm
Table: 5.3.1A Structural Joists and PlanksMoment Resistance
&Phi = 0.9
KH = 1.0
KH = 1.0
KD = 1
KT = 1.0
fb = 16.5 MPaKT = 1.0
KSb = 1.0
Sx = 124133mm3
Sy = 33693mm3
Kzb = 1.4
KLy = 1
KLx = 0.979
Mrx = &Phi*Fb*Sx*KZb*KLx = 2.527 kN*m
Mry = &Phi*Fb*Sy*KZb*KLy = 0.7 kN*m
Shear Resistance
&Phi = 0.9
KH = 1.0
KH = 1.0
KD = 1
KT = 1.0
fc = 1.9 MPaKT = 1.0
KSv = 1.0
An = 5320 mm2
Kzv = 1.4 Vr=&Phi*Fv*An*KZv/3 = 8.491 kN
Compression Resistance
&Phi = 0.8
KH = 1.0
KH = 1.0
KD = 1
KT = 1.0
fc = 19.0 MPaKT = 1.0
KSc = 1.0
A = b*d = 5320 mm2
Kzc_x = 1.3
Kzc_y = 1.3 Cc_x = 7.1 &le 50
Cc_y = 26.3 &le 50 Kse = 1.0
E05 = 8500 Kc_x = 0.97
Kc_y = 0.4Pr_x =&Phi*Fc*A*KZc_x*Kc_x = 102.036 kN
Pr_y =&Phi*Fc*A*KZc_y*Kc_y = 41.831 kN
Pr = 41.831 kN
Tension Resistance
&Phi = 0.9
KH = 1.0
KH = 1.0
KD = 1
KT = 1.0
ft = 10.6 MPaKT = 1.0
KSt = 1.0
An = b*d = 5320 mm2
Kzt = 1.3 Tr=&Phi*Ft*An*KZt = 65.98 kN
Deflection
E = 12500 MPa
Ix = b*d3/12 = 8689333 mm4
Iy = b3*d/12 = 640173 mm4
ES = E*KSE*KT = 12500MPa
Ix = b*d3/12 = 8689333 mm4
Iy = b3*d/12 = 640173 mm4
KSE = 1.0
KT = 1.0